b^2-3b+4=(b+2)(b+9)

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Solution for b^2-3b+4=(b+2)(b+9) equation: 



b^2-3b+4=(b+2)(b+9)

We move all terms to the left:

b^2-3b+4-((b+2)(b+9))=0

We multiply parentheses ..

b^2-((+b^2+9b+2b+18))-3b+4=0



We calculate terms in parentheses: -((+b^2+9b+2b+18)), so:

(+b^2+9b+2b+18)

We get rid of parentheses

b^2+9b+2b+18

We add all the numbers together, and all the variables

b^2+11b+18

Back to the equation:

-(b^2+11b+18)



We add all the numbers together, and all the variables

b^2-3b-(b^2+11b+18)+4=0

We get rid of parentheses

b^2-b^2-3b-11b-18+4=0

We add all the numbers together, and all the variables

-14b-14=0

We move all terms containing b to the left, all other terms to the right

-14b=14

b=14/-14

b=-1

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